#### Pengwuino

Gold Member

- 4,854

- 14

Ok I got this problem here...

http://img.photobucket.com/albums/v81/Veto1024/mercury.jpg [Broken]

How is this possible?!?!??!?!?!

If its pushing the mercury down the tube and back up into the atmosphere, the pressure has to be greater then 1atm yet the answer ends up being less then 1 atm inside the flask.

Also, we were tough to just add whatever the displacement was to 760 torr to find the correct pressure. Now I added (14.3in * 25.4 in/mm) + 760 torr to get 1122 torr which, when divided by 760, yields 1.48atm. Now even if I was wrong and was suppose to subtract, I would get (760-363.22) = 396.78 torr = .522atm yet even that's not what the program accepted.

What the crap? Is it wrong to use 760torr as standard atmospheric pressure?

http://img.photobucket.com/albums/v81/Veto1024/mercury.jpg [Broken]

How is this possible?!?!??!?!?!

If its pushing the mercury down the tube and back up into the atmosphere, the pressure has to be greater then 1atm yet the answer ends up being less then 1 atm inside the flask.

Also, we were tough to just add whatever the displacement was to 760 torr to find the correct pressure. Now I added (14.3in * 25.4 in/mm) + 760 torr to get 1122 torr which, when divided by 760, yields 1.48atm. Now even if I was wrong and was suppose to subtract, I would get (760-363.22) = 396.78 torr = .522atm yet even that's not what the program accepted.

What the crap? Is it wrong to use 760torr as standard atmospheric pressure?

Last edited by a moderator: