In a tornado, the pressure can be 15% below normal atmospheric pressure. Seomtimes a tornado can move so quickly that this pressure drop can occur in one second. Suppose a tornado suddnely occured outside your front door, whic is 182cm high and 91cm wide. what net force would be exerted on the door? in what direction would the force be exerted?(adsbygoogle = window.adsbygoogle || []).push({});

Answer: Fnet = Foutside-Finside

= (Poutside-pinside ) x a

= (0.85x10^5 Pa - 1x10^5 Pa ) x ( 1.82m)(0.91m)

= - 2.5x10^4 N( toward the outside )

The above answer is written at the back of the text book for the question typed above. However, i dont undersatnd where did they get the figures of .85x10^5 Pa and 1x10^5 Pa from..... can anyone please temme what those figures are?

thanks much

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# Homework Help: Pressure in a tornado and net force on a door

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