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Pressure in Beaker

  1. Sep 13, 2012 #1
    1. The problem statement, all variables and given/known data

    A 35 cm tall , 5 cm diamater cyldrical beaker is filled to its brim with water. whatis the donward force on the bottom of the beaker?
    2. Relevant equations

    p= po+ d*g*h
    F= p*A
    density of water is 1000
    3. The attempt at a solution

    p= 1.013*10^5 + 1000*9.8*0.35
    p = 104,730 Pa

    F= 104730 Pa * pi(0.025)^2 = 205.636 N

    Answer sheet says 210 newtons, and there are two sig digs in the question given. Either I did it wrong or Im supposed to round up. Let me know what is wrong please!!
  2. jcsd
  3. Sep 13, 2012 #2
    Bump, anyone?
  4. Sep 13, 2012 #3

    Doc Al

    User Avatar

    Staff: Mentor

    Looks OK to me. Round it up to two significant figures.

    (And don't be bumping after just 30 minutes!)
  5. Sep 13, 2012 #4
    Bumping is against the forum rules.

    It's due to roundoff. The net force on the bottom is onlly d*g*h.
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