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Pressure in tank

  1. Apr 8, 2016 #1
    1. The problem statement, all variables and given/known data
    in this question , the author stated that the P1 = P atm , but at point 1 , the gas tank is not open to the atmosphere, it is a closed tank . so , is the author wrong ? again , at point 2 , the tank isn't open to atmosphere, why it is P2= P atm ?

    2. Relevant equations


    3. The attempt at a solution
     

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  3. Apr 8, 2016 #2

    gneill

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    Staff: Mentor

    Why might the two pressures be P atm? Can you think of any reason? How does the small diameter hose reach the liquids?
     
  4. Apr 8, 2016 #3
    i dont think P1 and P2 = P atm .....
     
  5. Apr 8, 2016 #4

    gneill

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    Staff: Mentor

    I understand that. But can you think of any way that they could?
     
  6. Apr 8, 2016 #5
    for P1 = P2 = P atm , the tank is not closed?
     
  7. Apr 8, 2016 #6

    gneill

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    Staff: Mentor

    Correct. How does the hose enter each tank?

    upload_2016-4-8_10-59-47.png
     
  8. Apr 8, 2016 #7
    at point 1 , it is immersed in the gas tank , while the point 2 is at the hole only , not completely immersed . What are you trying to tell ?
     
  9. Apr 8, 2016 #8

    gneill

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    Staff: Mentor

    I'm pointing out that neither tank is sealed. Both are open to the atmosphere through their filling apertures. The siphon hose does not make an air-tight seal at either opening.
     
  10. Apr 8, 2016 #9
    if that is air-tight selaed , then the pressure acting would not be P atm anymore , am i right ?
     
  11. Apr 8, 2016 #10

    gneill

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    Staff: Mentor

    Sure. It might start out at P atm at the moment a seal was made though.

    But there is no seal mentioned in the problem statement. The assumption is that, as in the real-life situation for siphoning gas in this manner, the hose fits loosely through the gas cap opening and down into the liquid.
     
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