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How does changing altitude affect the pressure inside a balloon?
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[QUOTE="jack action, post: 5496841, member: 240508"] A balloon is an elastic. To deform an elastic, you must provide a force. If the force inside is greater than the one outside, the area extends. Since we're talking about force and area, we can also talk about pressure. If a balloon has deformed, then the pressure inside has to be greater than the one outside. The greater the deformation, the greater the pressure differential (P[SUB]in[/SUB] - P[SUB]out[/SUB]). This takes care of your points 1 & 2. For point 3, what happens is that you are reducing the outside pressure which has the same effect as increasing the inside pressure, i.e. increasing the deformation of the balloon. The interesting thing is that the inside of the balloon is a closed system so, as the balloon increases in volume, the inside pressure will also decrease. The equilibrium will be reached faster, so the increase in size will be smaller than one could have initially thought. [/QUOTE]
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How does changing altitude affect the pressure inside a balloon?
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