1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Pressure/Mass Relationship

  1. Apr 9, 2008 #1
    [SOLVED] Pressure/Mass Relationship

    1. The problem statement, all variables and given/known data

    [tex]H_{2}[/tex] gas was obtained by the displacement of [tex]H_{2}O[/tex] at total pressure of 833 torr. The volume of the obtained gas was .5 Liters and the vapor pressure of [tex]H_{2}O[/tex] was 22 torr. Find the mass of [tex]H_{2}[/tex] gas.

    2. Relevant equations

    [tex]P_{tot} = P_{1} + P_{2}[/tex]
    [tex] P_{tot} = (n_{1} + n_{2})(\frac{RT}{V})[/tex]
    [tex] P_{1} = (n_{1})(\frac{RT}{V})[/tex]
    [tex] P_{2} = (n_{2})(\frac{RT}{V})[/tex]

    3. The attempt at a solution

    Now here is my attempt, which I'm definitely not sure of:

    [tex]P_{tot} = P_{H_{2}O} + P_{H_{2}} \Rightarrow P_{H_{2}} = 833 - 22 = 811[/tex]


    [tex]n_{H_{2}} = \frac{PV}{RT} = \frac{(811)(0.5)}{(0.082)(295)} = 16.7[/tex]

    And then trivially obtain the mass of hydrogen in the experiment:

    [tex]m_{H_{2}} = (2)(16.7) = 33.4 g[/tex]

    Is this correct? I'm not sure of how I obtained [tex]P_{H_{2}}[/tex].
    Last edited: Apr 9, 2008
  2. jcsd
  3. Apr 10, 2008 #2
    I'm going to assume this was at a temperature of 295°K, because that's what you used in your calculations, but you didn't state this in the problem.

    You calculated the pressure of the hydrogen gas correctly. The total pressure of the gas is 833 torr, with H2O gas accounting for 22 torr of that pressure. This means that the hydrogen gas is responsible for the remaining 811 torr of pressure.

    The equation you used was fine, but you didn't use the correct "R" value. If you use torr for pressure, you can't use 0.0821 for the R value. Divide the pressure by 760 to convert to atmospheres, which then lets you use 0.0821 for the R value. Or you can use the proper R value for when you have a pressure measured torr, but I prefer to only have to memorize R value.

    So just divide the answers you got by 760 and they will be correct.
  4. Apr 11, 2008 #3
    Thanks nautikal!
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Pressure/Mass Relationship