- #1

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1 atom per cm^3 => 10^6 per m^3.

It's a low pressure so I guess I can use the ideal gas equation. I also know the mass of a helium atom is 6.68x10^-27 kg.

What's the best route forward?

Best Regards, James.

- Thread starter capslock
- Start date

- #1

- 17

- 0

1 atom per cm^3 => 10^6 per m^3.

It's a low pressure so I guess I can use the ideal gas equation. I also know the mass of a helium atom is 6.68x10^-27 kg.

What's the best route forward?

Best Regards, James.

- #2

Hootenanny

Staff Emeritus

Science Advisor

Gold Member

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Why are you trying to calculate the pressure?

Either way you can use:

[tex]pV= nRT [/tex]

where [itex]n[/itex] is the number of moles and [itex]R = 8.31 J\cdot mol^{-1}\cdot K^{-1}[/itex] and is the molar gas constant.

You will first need to convert the mass and density into a volume.

Hope this helps.

Either way you can use:

[tex]pV= nRT [/tex]

where [itex]n[/itex] is the number of moles and [itex]R = 8.31 J\cdot mol^{-1}\cdot K^{-1}[/itex] and is the molar gas constant.

You will first need to convert the mass and density into a volume.

Hope this helps.

Last edited:

- #3

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That's great. Thanks.Hootenanny said:Hope this helps.

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