- #1

nazarian

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Thanks, excuse me if my english is not correct.

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- Thread starter nazarian
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- #1

nazarian

- 2

- 0

Thanks, excuse me if my english is not correct.

- #2

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Does that help you?

- #3

nazarian

- 2

- 0

Let me use a simpler question;

Asume the pressure is constant, H is the height, R is the radius, [itex]\hat{i}[/itex] is the direction perpendicular to de plane of the screws. The resultant force on one half is then [itex]\vec{F}=\pi PHR \hat{i}[/itex] or [itex]2PHR \hat{i}[/itex]?. The 2 comes from integrating [itex]sin\theta[/itex] between 0 and [itex]\pi[/itex], while the first expression comes from integrating without [itex]sin\theta[/itex]

- #4

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Btw, are you supposed to worry about gravity too?

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