- #1
jumbogala
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Homework Statement
I'm having some trouble with the concept of pressure, so I'd like to make sure I'm not doing this wrong!
What is the pressure 45 m underwater?
Homework Equations
P = Patm + ρgh
The Attempt at a Solution
Density of seawater = 1020 kg/m3
Patm = 101300 Pa
So P = 101300 Pa + (1020 kg/m3)(9.81 m/s2)(45 m) = 154 274 Pa or 154 kPa.
My question is - the pressure on something huge should be the same as the pressure on something small, right?
Also, I read something about the pressure on a diver being the atmospheric pressure plus the water pressure. But the atmospheric pressure is taken into account already by the formula used, so I don't need to add it in again, correct?
Thanks :)
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