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## Homework Statement

I'm having some trouble with the concept of pressure, so I'd like to make sure I'm not doing this wrong!

What is the pressure 45 m underwater?

## Homework Equations

P = P

_{atm}+ ρgh

## The Attempt at a Solution

Density of seawater = 1020 kg/m

^{3}

P

_{atm}= 101300 Pa

So P = 101300 Pa + (1020 kg/m

^{3})(9.81 m/s

^{2})(45 m) = 154 274 Pa or 154 kPa.

My question is - the pressure on something huge should be the same as the pressure on something small, right?

Also, I read something about the pressure on a diver being the atmospheric pressure plus the water pressure. But the atmospheric pressure is taken into account already by the formula used, so I don't need to add it in again, correct?

Thanks :)

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