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Pressure system

  1. Jan 19, 2006 #1
    I'm trying to remember how to calculate the equlibrium height of a system of 2 cylinders connected by a tube at the bottom with the smaller cylinder open to the atmosphere and 702.9N pressing down on the other side.

    I believe it has to do with the pressure being equal on both sides or potential energy being equal, its been a while since I did these, can anyine refresh my memory? Thanks.
  2. jcsd
  3. Jan 19, 2006 #2
    Not 100%

    For U tube, with 1 end open to atmosphere, the unknown P(kPa)=density (1 for water) * gravity (9.8) * delta Heighth (meters).

    I think you would need the diameter of the cylinder with the wieght on it to calculate the pressure on that side. The other side would rise up until the delta H is equal to the pressure in the cylinder.
  4. Jan 19, 2006 #3
    thanks for your help.
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