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Pressure under water

  1. Nov 18, 2009 #1
    1. The problem statement, all variables and given/known data
    Calculate thy pressure 150m below the surface of za sea. The density of sea water is 1.026 g/cm3.


    2. Relevant equations & The attempt at a solution
    The pressure will depend on how much water is above you...

    F = mg
    F = pVg --- since density = mass per volume
    F = pAdg --- since volume = area * depth
    F/A = pdg
    Therefore Pressure = pdg

    ------conversion of units--------
    9.8 m/s2 * 100 cm/1 m = 980 cm/s2
    150 m = 15 000 cm
    --------------------------------

    P = (1.026 g/cm3) * 150 000 cm * (980 cm/s2)
    P = 150 822 000 g/cm2

    But my textbook says 1.51 x 107 dyn/cm2 (= 15 atm)

    So is my textbook wrong, or what did I do :redface: ?
     
  2. jcsd
  3. Nov 18, 2009 #2
    Btw, what is dyn?
     
  4. Nov 18, 2009 #3

    Borek

    User Avatar

    Staff: Mentor


    http://en.wikipedia.org/wiki/Dyne

    --
     
  5. Nov 18, 2009 #4
    :frown:

    Thanks.
     
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