Prime for x Floor[3^(3^x)]

1. Nov 6, 2006

Dragonfall

I think I read this somewhere, but I'm not sure it's right: is there a real number A such that Floor[A^(3^x)] is prime for all x?

Last edited: Nov 6, 2006
2. Nov 6, 2006

0rthodontist

That doesn't make any sense.

3. Nov 6, 2006

CRGreathouse

Are you thinking perhaps of Mills' constant?

4. Nov 6, 2006

Dragonfall

Mill's constant! That's the one.

5. Nov 7, 2006