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Prime for x Floor[3^(3^x)]

  1. Nov 6, 2006 #1
    I think I read this somewhere, but I'm not sure it's right: is there a real number A such that Floor[A^(3^x)] is prime for all x?
    Last edited: Nov 6, 2006
  2. jcsd
  3. Nov 6, 2006 #2


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    That doesn't make any sense.
  4. Nov 6, 2006 #3


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    Are you thinking perhaps of Mills' constant?
  5. Nov 6, 2006 #4
    Mill's constant! That's the one.
  6. Nov 7, 2006 #5
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