Please any idea on this,find the primitive of arctan x
Two ways: Make the substitution u=arctan x, or use integration by parts,
[tex]\int u \ dv = uv - \int v \ du[/tex]
where dv=dx, u=arctan x (they really work out in the same way anyways).
Yah now I understand it will be the intergral of arctanxdx. thanx.
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