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Prism question

  1. Apr 15, 2008 #1
    1. The problem statement, all variables and given/known data

    A light ray is incident on a prism whose apex angle is 65.0°. The ray is
    incident at θa and leaves the prism with θa = θd. The refractive index of
    the prism glass is 1.54.
    Calculate θ



    ans:55.8°

    2. Relevant equations

    n1sin[tex]\phi[/tex]1=n2sin[tex]\phi[/tex]2

    3. The attempt at a solution

    please help
     
  2. jcsd
  3. Apr 15, 2008 #2
    prism.jpeg

    See attachment before reading.

    If the apex angle is 65 degrees, that means that our base angles are x = (180-65) / 2 = 57.5 degrees.

    Now we know that the angle that the light enters the prism is equal to the angle that it leaves, this is another way of saying that the light travels parallel to the base of the prism. By simple trigonometry, we can determine angle θ2. Remember, θ2 is measured relative to the normal of incidence, N.(perpendicular to incident surface of prism).

    θ2 = 90 - 57.5 = 32.5 degrees.

    Once this is determined, we need to use Snell's law.

    We've just found θ2 through geometry, and we're after θ1.

    Regards,
    Rob.
     
    Last edited: Apr 15, 2008
  4. Apr 15, 2008 #3
    ohhh i get it. Thanks a lot.
     
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