# Probability anyone?

1. Dec 8, 2004

### ms. confused

Can anyone tell me how I would solve this question:

A bag contains 3 white balls and 2 black balls. The first draw produced a white ball. The first ball is not replaced. What is the probability that the second draw will produce another white ball?

2. Dec 8, 2004

### dextercioby

You mean it's not put in the bag again.Okay...
Hint:What was the probability of pulling a white ball in the beginning??What is the formula of probabilities??How would you go abot now...??

Please,show me how you think.The purpose of this forum is to guide U solve the problem,not me..!!

3. Dec 8, 2004

### ms. confused

Ok well i see the probability of drawing a white ball at the beginning as being 2/5

4. Dec 8, 2004

### uranium_235

Might want to recheck your work.

5. Dec 8, 2004

### dextercioby

How did u figure that out...??It's important to show your judgement,as well,since apparently it is to blame for erroneous results...
Again...??What' the initial probability and why.......??????????

6. Dec 8, 2004

### HallsofIvy

Staff Emeritus
No, at the beginning the bag contained 5 balls, 3 of which were white.
The probability of drawing a white ball, at the beginning was ?/5.

However, your original question is different. After drawing a white ball out, the bag has 4 balls left, 2 of which are white. What is the probability of drawing a white ball now?

7. Dec 8, 2004

### ms. confused

When simplified the probability now is 1/2.