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Probability at Minima or Maxima

  1. Oct 16, 2007 #1
    I hate to make another topic so soon, but I'd like to get some opinions on this question...

    1. The problem statement, all variables and given/known data
    A two slit electron difraction experiment is done with slits of unequal widths. When only slit 1 is open, the number of electrons reaching the screen per second is 25 times the number of electrons reaching the screen per second when only slit 2 is open. When both slits are open, an interference pattern results in which the destructive interference is not complete. Find the ratio of the probability of an electron arriving at the interference maximum to the probability of an electron arriving at an adjacent interference minimum.


    2. Relevant equations

    Superposition principle, of course.

    |(psi1)^2 +(psi2)^2| (?)

    Maxima at (theta) = h/(pD) (?)
    Minima at (theta) = h/(2pD) (?)

    Group velocity and/or Phase Velocity?



    3. The attempt at a solution

    According to the book, the solution should be 2.25:1. Problem is, I don't quite know where to begin with the question. I'm running on practically no sleep right now and probably am just skipping over something to kick off the question, so if I could just get a little nudge in the right direction I could probably figure this out on my own.
     
  2. jcsd
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