So, there is a deck of 10 card and a player picks 3 cards(adsbygoogle = window.adsbygoogle || []).push({}); one at a timewithout replacement. What is the probability that the three cards are selected in sorted (increasing) order?

I am not fully understand this question, for me there are two possibilities:

1. The final three cards are sorted in order. (e.g. 1st = 3, 2nd = 1, 3rd = 2)

2. Or, it is strictly increasing, 1st card < 2nd card < 3rd card.

I do favor the 2nd possibility but i can not convince my self, perhaps anyone can help me.

So, my approach is (for the 2nd possibility) to group those 10 cards to a group of 3 cards (in increasing order). Lets call it A, so

A = {(1,2,3),(2,3,4),(3,4,5),(4,5,6),(5,6,7),(6,7,8),(7,8,9),(8,9,10)}

and S is 10x9x8.

So P(A) = 8/(10x9x8) = 1/90

Is this the right thing to do??

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Probability card questions

**Physics Forums | Science Articles, Homework Help, Discussion**