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## Homework Statement

- Initial conformational potential energy = 2500 J

- NVT Metropolis Monte Carlo simulation, T = 300 K

- New conformational potential energy = 5000 J

What's the probability this will be accepted within the Metropolis scheme?

## Homework Equations

Acceptance Probability:

[tex]P=exp\left(\frac{-\Delta U_{mn}}{kT}\right)[/tex]

[tex]\Delta U_{mn}=U(q_{n}^{N})-U(q_{m}^{N})[/tex]

where [tex]U(q_{m}^{N})[/tex] is our initial potential and [tex]U(q_{n}^{N})[/tex] is our final potential.

## The Attempt at a Solution

I'm plugging these numbers in, but the exponent is going to zero, which I know to be wrong. Is there some conversion of energy I'm missing? Seems a bit odd...