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Probability Help

  1. Mar 12, 2007 #1
    1. The problem statement, all variables and given/known data

    The question states: The probablity that a carton of eggs has a (at least one) cracked egg is .04. What is the probability that your carton is fine?


    2. Relevant equations



    3. The attempt at a solution

    I'm not sure how to go about this one. I'm pretty comfortable with the beginning probability stuff, but I'm sure as to which equation applies here. If someone can point me in the right direction I would be so grateful.

    Thank you very much.
     
  2. jcsd
  3. Mar 12, 2007 #2

    Dick

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    What is the sum of the probabilities that i) the carton contains at least one cracked egg and ii) the carton contains no cracked eggs?
     
  4. Mar 12, 2007 #3
    Think about it, if the probability of having AT LEAST 1 is 0.04, what is the probability of having NONE?

    For another question with a similiar answer that may help you understand what the question is asking:

    If the probability of winning a draw is 5%(no ties are possible), what is the probability that you will lose? Well what are the possibilities... You could either win or lose. So if you have a 5% chance of winning, you must have a 95% chance of losing.

    edit: As Dick said, the sum of all the possible outcomes is always 1.00 (100%). So p(at least 1) + p(0) = 1, right?
     
    Last edited: Mar 12, 2007
  5. Mar 12, 2007 #4
    That completely makes sense now. I feel kind of stupid now cause it's actually super easy.

    Thank you for helping.
     
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