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Probability math homework help

  1. Jan 27, 2008 #1
    An aircraft requires [tex] 25 [/tex] rivets. The seam will have to be reworked if any of these rivets is defective. Suppose rivets are defective independently of one another, each with same probability.

    (a) If [tex] 20 \% [/tex] of all seams need reworking, what is the probability that a rivet is defective?

    So this is equaled to [tex] \frac{1}{25} [/tex]?

    (b) How small should the probability of a defective rivet be to ensure that only [tex] 10 \% [/tex] of all seams need reworking?
  2. jcsd
  3. Jan 28, 2008 #2


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    Have you learned about binomial distribution yet?
  4. Jan 28, 2008 #3
    figured it out, thanks.
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