Probability mutual exclusive homework problem

[Sombra]

Given that p(A)=0.6 and p(B)= 0.7 and that A and B are independent, find the probabilty of
a. A or B
b. A and B

I don't understand this because if 2 events are independent, then they are not mutually exclusive. So, A and B does not = 0, but that's all I know and I need A and B to solve for A or B. Help! Thanks

 

[ShawnD]

Originally posted by Sombra
Given that p(A)=0.6 and p(B)= 0.7 and that A and B are independent, find the probabilty of
a. A or B
b. A and B

b).
Just multiply the two together.
(0.6)(0.7) = 0.42

a).
For this one you have to find the probability of A only, B only, A and B. Then you just add those.
A only:
(0.6)(1-0.7) = 0.18
B only:
(1-0.6)(0.7) = 0.28
A and B:
(0.6)(0.7) = 0.42

Sum of those:
0.18 + 0.28 + 0.42 = 0.88

 

[Sombra]

¡Muchas gracias! That helped a lot