Probability of 5 dice rolled

In summary, the formula for calculating the probability of getting a 5 of a kind, 4 of a kind, 3 of a kind, pair, and straight when rolling 5 dice is (how many kinds)*(probability of getting n of the kind)*(how many ways to get the n). For a 5 of a kind, the formula is 6*(1/6)^5*1. For a 4 of a kind, it is 6*(1/6)^4*(5/6)*5. Creative thinking or a general formula using combinatorial coefficients can be used to calculate the probabilities for each case.
  • #1
Susan0814
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When rolling 5 dice one time for each, what is the formula to figure the probability of getting a 5 of a kind, 4 of a kind, 3 of a kind, pair, and a straight.
I used 6*(1/6*1/6*1/6*1/6*1/6) to get the probability of 5 of a kind and came up with 6/7776. What formulas do I use to get the others or how do I alter the formula?
 
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  • #2
You are off to a good start. The formula is (how many kinds)*(probability of getting n of the kind)*(how many ways to get the n). You've correctly done the five of a kind as 6*(1/6)^5*1. Now let's do 4. The first number is the same. The second number becomes (1/6)^4*(5/6) (four must be the selected number and the fifth can't). The last number is how many ways can this happen. Any of the 5 numbers can be nonmatching so 5. So 6*(1/6)^5*(5/6)*5. You can creatively make these up for each case, or you can think of some general formula you've been taught to apply. Hint: one of the numbers is called a combinatorial coefficient.
 
  • #3


To calculate the probability of getting a 4 of a kind, 3 of a kind, or a pair, you can use the following formula:

Number of ways to get the desired outcome / Total number of possible outcomes

For a 4 of a kind, there are 6 ways to choose the number that will appear 4 times, and 5 ways to choose the remaining die. This gives us a total of 6*5 = 30 ways to get a 4 of a kind. The total number of possible outcomes when rolling 5 dice is 6^5 = 7776. So the probability of getting a 4 of a kind is 30/7776 or approximately 0.00386.

For a 3 of a kind, there are 6 ways to choose the number that will appear 3 times, and 5C2 = 10 ways to choose the remaining two numbers. This gives us a total of 6*10 = 60 ways to get a 3 of a kind. So the probability of getting a 3 of a kind is 60/7776 or approximately 0.00772.

For a pair, there are 6 ways to choose the number that will appear twice, and 5C3 = 10 ways to choose the remaining three numbers. This gives us a total of 6*10 = 60 ways to get a pair. So the probability of getting a pair is 60/7776 or approximately 0.00772.

To calculate the probability of getting a straight, you can use the following formula:

Number of ways to get a straight / Total number of possible outcomes

There are 6 possible straight combinations (12345, 23456, 34567, 45678, 56789, 67891) and each can appear in 5 different ways (since the first die can be any number). So the total number of ways to get a straight is 6*5 = 30. The total number of possible outcomes when rolling 5 dice is 6^5 = 7776. So the probability of getting a straight is 30/7776 or approximately 0.00386.

In summary, the formulas to calculate the probability of getting a 5 of a kind, 4 of a kind, 3 of a kind, pair, and a straight when rolling 5 dice are as follows:

5 of a kind
 

1) What is the probability of rolling a specific number on all 5 dice?

The probability of rolling a specific number on all 5 dice is 1 out of 6 raised to the 5th power, or 1/6^5. This is because each dice has a 1/6 chance of landing on the specific number, and since each roll is independent, we multiply the probabilities together.

2) What is the probability of rolling a total of 7 on 5 dice?

The probability of rolling a total of 7 on 5 dice is 6/7776, or approximately 0.077%. This can be calculated by finding the number of ways to roll a total of 7 (6) and dividing it by the total number of possible outcomes (7776).

3) How many ways can 5 dice be rolled to get a sum of 15?

There are 25 ways to roll 5 dice and get a sum of 15. This can be calculated by using a combination formula, which takes into account the order of the dice rolls. The formula is nCr = n! / (r!(n-r)!), where n is the total number of dice (5) and r is the desired sum (15).

4) What is the probability of getting a full house (3 of a kind and a pair) when rolling 5 dice?

The probability of getting a full house when rolling 5 dice is approximately 0.038%, or 1/2592. This can be calculated by finding the number of ways to get 3 of a kind (6) and the number of ways to get a pair (25), and dividing it by the total number of possible outcomes (7776).

5) How does changing the number of dice rolled affect the probability of certain outcomes?

The more dice that are rolled, the more the probabilities of certain outcomes will approach their theoretical values. For example, as the number of dice rolled increases, the probability of rolling a specific number on all of them will approach 0. Similarly, the probability of rolling a total of 7 will approach 0.077% as the number of dice increases. This is because the more dice that are rolled, the more likely it is for the outcomes to even out and for the probabilities to align with their theoretical values.

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