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Probability of an event

  1. Dec 26, 2013 #1

    Qube

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    1. The problem statement, all variables and given/known data

    A woman has 5 tickets for a contest. There are 1,000 tickets total. Two tickets out of those 1,000 tickets will deem people as winners and they will receive prizes. What is the probability that the woman with the 5 tickets will win a prize?

    2. Relevant equations

    Could you find the complement of the event and subtract the probability of the complement from 1?

    3. The attempt at a solution

    Complement = P(Not getting a winning ticket)

    998 non-winning tickets. Probabilities:

    1/998 * 1/997 * 1/996 * 1/995 * 1/994 = P(Not getting a winning ticket)

    Subtract the above from one.

    However, the fact she has five tickets complicates matters; what do I do?
     
  2. jcsd
  3. Dec 26, 2013 #2

    vela

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    You already took into account that she has five tickets when calculating the probability she wouldn't have a winning ticket.
     
  4. Dec 26, 2013 #3

    Qube

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    So I can just subtract the complement from 1?
     
  5. Dec 26, 2013 #4

    vela

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    Yup.
     
  6. Dec 26, 2013 #5

    vela

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    Oops, you calculated the probability incorrectly. She has 998 ways out of 1000 to pull the first non-winning ticket, not 1 out of 998, and so on.
     
  7. Dec 26, 2013 #6

    Qube

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    You're right. I actually calculated it correctly before I transcribed my work to PF. It's 998/1000 * 997/999 * 996/998 ...
     
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