- #1

- 11

- 0

I'm having difficulty time of trying to figure out answer.

Question:

P(A^c U B) = 0.6

P((A^c U B^C) = 0.8

Find P(A) ?

Sol:

P(A^c U B) = P(A^c) + P(B) - P(A^c Intersection B)

P(A^c U B^c) = P(A^c) + P(B^c) - P(A^c Intersection B^c)

0.6 + 0.8 = 2*P(A^c) + 1 - P(A^c) <==== HOW ?????????

P(A^c)=0.4, P(A)=1-P(A^c)=0.6

PROBLEM:

I have the solution, but I don't get how he got "- P(A^c)"

I think my instructor skipped some steps.

Question:

P(A^c U B) = 0.6

P((A^c U B^C) = 0.8

Find P(A) ?

Sol:

P(A^c U B) = P(A^c) + P(B) - P(A^c Intersection B)

P(A^c U B^c) = P(A^c) + P(B^c) - P(A^c Intersection B^c)

0.6 + 0.8 = 2*P(A^c) + 1 - P(A^c) <==== HOW ?????????

P(A^c)=0.4, P(A)=1-P(A^c)=0.6

PROBLEM:

I have the solution, but I don't get how he got "- P(A^c)"

I think my instructor skipped some steps.

Last edited: