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Probability problem (counting)

  1. Sep 28, 2010 #1
    *******************I am sorry about this, Please Use My other post

    1. The problem statement, all variables and given/known data

    A football team consists of 20 offensive and 20 defensive players. Th players are to be paired to form roommates. They are paired at random. What is the probability that there are exactly 4 offensive/defensive pairs.

    2. Relevant equations

    3. The attempt at a solution

    See attachment

    motivation: -(4!)2 ways to pair up the players.
    -[tex]\frac{40!}{20!(2)^20}[/tex] total ways to pick 20 pairs
    -(20 choose 4)2 ways to pick the 4 players to be paired up
    -[tex]\frac{32!}{16!(2)^16}[/tex] ways to pair up the rest of the guys
    Last edited: Sep 28, 2010
  2. jcsd
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