there is a pile of diodes. Half of them are checked. The pile is declared valid, if there are no more than 2% of broken diodes.(adsbygoogle = window.adsbygoogle || []).push({});

Now i have to find the probability when having a pile of 100 diodes and 5% of them are broken, would be declared valid.

How i did this task. there are 95 "ok" diodes and 5 broken diodes. The probability of this set of diodes declared valid isp(A)= (95C48*5C2 + 95C49*5C1 + 95C50*5C0)/100C50which equals0.5. The answer after the problem is said to bep(A)= 0,181

Am I thinking wrong?

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# Homework Help: Probability problem

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