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Now i have to find the probability when having a pile of 100 diodes and 5% of them are broken, would be declared valid.

How i did this task. there are 95 "ok" diodes and 5 broken diodes. The probability of this set of diodes declared valid is

**p(A)= (95C48*5C2 + 95C49*5C1 + 95C50*5C0)/100C50**which equals

**0.5**. The answer after the problem is said to be

**p(A)= 0,181**

Am I thinking wrong?