Team 0 and Team 1 have played 1000 games and Team 0 has won 900 of them.[/B]
When the two teams play next, knowing only this information, which team is more likely to win?
P(X,Y) = P(YlX) x P(X) = P(XIY) x P(Y) (Not Sure)
The Attempt at a Solution
I am trying to solve it using Bayes Theorem. Kindly guide me is it correct or not?
Probability of Team 1 winning = 100/1000 = 0.1
Probability of Team 2 winning = 900/1000 = 0.9
Probability of Team 1 losing = 900/1000 = 0.1
Probability of Team 2 losing = 100/1000 = 0.1
Let X represents the Probability of Team winning the match
Let Y represents the Probability of Team losing the match
P(X=1|Y=0) = P(X=0|Y=1)