A coin is tossed 4 times. What is the probability of getting more heads than tails?
Use the binomial distribution.
I'm guessing about 25%
Juvenal's suggestion is good, but I thought I'd give you an alternate way of solving the problem. What is the probability of a certain combination och heads and tails? For example: first throw you ger tail, the three following throws heads come up. Then, think about in how many such combinations you would get more heads than tails.
is there.. a formula for it..
if its tossed 4 times.. and there are 2 sides..
wouldn't it be 4 choose 2???
if there are more H that t woudl it be HHH and T...
i hate probability questions..
The formula for the binomial distribution is standard, and you don't have to think.
Every time you throw there is 50% chance of T and 50% of H.
So, if you throw once you have (P(x)=probability that x happens):
If you thow twice:
If you throw four times there is 1/16 chance you'll get one of the 16 combination:
1. HHHH, 2. HHHT, 3. HHTH,... etc.
These three examples are all more Heads than Tails, how many more such combinations are there? If you can answer that, you're done.
I get it.. thanx.. u guys helped me graduate..(LOL).. awesome..
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