Probability question

  • Thread starter crays
  • Start date
  • #1
160
0
Hi, i have this question
A bag contains 5 red balls, 10 blue balls and 15 green balls. Three balls are drawn from the bag one after another without replacement. The event R1 , R2 , B2 and G3 are defined as follows.

R1 - represents the event the first ball drawn is red.
R2 - represents the event the second ball drawn is red.
B2 - represents the event the second ball drawn is blue.
G3 - represents the event the third ball drawn is green.

Find
a) i) P(R1 [tex]\cap[/tex] R2)

for this , i drew a tree diagram, for it to be red for the first ball, it has to be 5/30 and for the second to be red it has to be 4/29 thus multiplying them both would give me the answer which is 2/87.

ii) P(R1 [tex]\cup[/tex] R2)

for this i thought of P(R1) + P (R2) - P(R1 [tex]\cap[/tex] R2) would solve the problem but the answer is incorrect and later i see, i don't really know what's the probability of R2 because it could be 5/29 or 4/29.

Please help.
 

Answers and Replies

  • #2
Dick
Science Advisor
Homework Helper
26,260
619
You see the problem correctly. You could add up the separate cases i) first red, second not red, ii) first not red, second red and iii) both red. But it might be easier to notice that is equal to 1-(first not red)*(second not red).
 
  • #3
statdad
Homework Helper
1,495
35
You have this on another part of this site - look over there.
 

Related Threads on Probability question

  • Last Post
Replies
11
Views
896
  • Last Post
Replies
3
Views
931
  • Last Post
Replies
4
Views
847
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
2
Views
916
  • Last Post
Replies
0
Views
960
J
  • Last Post
Replies
2
Views
968
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
3
Views
1K
Top