(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

In a population of children 60% are vaccinated against the 'waterpokken'. The probablilities of contracting 'waterpokking' are 1/1000 if the child is vaccinated and 1/100 if not.

a: Find the probability that a child selected at random will contract 'waterpokken'.

2. Relevant equations

Bayes Theorem: P(A|B) = P(A/\B) / P(B)

Formula sheet? View attachment stat_formulas.pdf

3. The attempt at a solution

Known values: P(V) = 0.6 | P(⌐V) = 0.4 | P(W|V) = 0.001 | P(W|⌐V) = 0.01

a: Find the probability that a child selected at random will contract 'waterpokken'.

- The question is: what is P(W)?

From Bayes Theorem I conclude: P(W) = P(V/\W) / P(V|W)

Both P(V/\W) & P(V|W) are unkown at this stage.

- P(V/\W)?

Fill in known values in bayes theorem:

P(W|V) = P(W/\V) / P(V) = 0.001 = P(W/\V) / 0.6

So: P(V/\W) = P(W/\V) = P(V) * P(W|V) = 0.6 * 0.001 = 0.0006

Until here I get it! But now...

- P(V|W)?

P(V|W) = P(V/\W) / P(W) but I don't know P(W) :S?

Answer sheet solution:

P(W/\⌐V) = P(W|⌐V) = 0.01 * 0.4 = 0.004

P(W) = P(W/\V) + P(W/\⌐V) = 0.0006 + 0.004 = 0.0046

1. What rules are applied in the third section? Could someone explain to me how they conclude to

P(W/\⌐V) = P(W|⌐V) and P(W) = P(W/\V) + P(W/\⌐V) ?

Maybe it's part of the formulas at the bottom of the first page of my formula sheet View attachment stat_formulas.pdf

2. Is there a way I could have known that I would need to work to that solution. Because I concluded I needed to work towards P(W) = P(V/\W) / P(V|W) but that plainly doesn't work..:(

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# Homework Help: Probability Question

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