Probability Question

  • Thread starter Xenix
  • Start date
  • #1
6
0
I am given this probability table:

x 0 1 2 3 4
P(X=x) 0.8 0.1 0.05 0.03 0.02

X is the amount of faulty products produced in a day.

I am being asked to find the probability of a exactly one product being foulty in a 5 day periode.

I am a bit confused. I know from the table that the probability of exactly one faulty product in 1 day is 0.1.
But for 5 days, is it that ease just to multiply 0.1 by 5? Or is it 0,1^5?
 

Answers and Replies

  • #2
Dick
Science Advisor
Homework Helper
26,260
619
I am given this probability table:

x 0 1 2 3 4
P(X=x) 0.8 0.1 0.05 0.03 0.02

X is the amount of faulty products produced in a day.

I am being asked to find the probability of a exactly one product being foulty in a 5 day periode.

I am a bit confused. I know from the table that the probability of exactly one faulty product in 1 day is 0.1.
But for 5 days, is it that ease just to multiply 0.1 by 5? Or is it 0,1^5?

No, it's not that simple. One of the days has to have a single faulty product. The other four days have to have no faulty products.
 
  • #3
6
0
Ok, thank you for your answer, so then 0.1*(4*0.8)?
 
  • #4
Dick
Science Advisor
Homework Helper
26,260
619
Ok, thank you for your answer, so then 0.1*(4*0.8)?

No, the probability of something with probability 0.8 happening on 4 days isn't (4*0.8). That's bigger than 1! This an example of a binomial distribution problem. Don't you have a lesson on that?
 
  • #5
6
0
Thanks again for the answer. It turns out there is a scheduling conflict at the uni and we are not supposed to cover that topic until next week, however the assignment is due Monday.
I managed to solve this though.
Thanks for your help! :)
 
  • #6
Dick
Science Advisor
Homework Helper
26,260
619
Thanks again for the answer. It turns out there is a scheduling conflict at the uni and we are not supposed to cover that topic until next week, however the assignment is due Monday.
I managed to solve this though.
Thanks for your help! :)

Good work. I was wondering why you seemed to be missing a lot of the basics to tackle this problem.
 

Related Threads on Probability Question

  • Last Post
Replies
11
Views
903
  • Last Post
Replies
5
Views
1K
  • Last Post
Replies
5
Views
818
  • Last Post
Replies
2
Views
765
  • Last Post
Replies
8
Views
989
  • Last Post
Replies
7
Views
897
  • Last Post
Replies
0
Views
1K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
2
Views
918
  • Last Post
Replies
2
Views
969
Top