1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Probability with dice

  1. Oct 27, 2014 #1
    1. The problem statement, all variables and given/known data
    A pair of dice is loaded. The probability of 4 appearing on the first die is 2/7.
    and the probability of a 3 appearing on the second die is thrice as much as the other numbers
    on the die. If the rest of the numbers are equally likely events in both dice, what is the
    probability of 7 appearing as the sum of the numbers when the two dice are rolled.

    3. The attempt at a solution

    So I was wondering if the answer I got is correct by chance. I took all the cases.
    1 6
    6 1
    2 5
    5 2
    3 4
    4 3

    Got the probabilities and added them up. But I am not sure I got it right because it says the rest of the numbers are equally likely to appear, does that mean the probability of the rest in both dice is exactly the same. This is because if the probability of rolling a 4 on the first die is 2/7 then the rest are
    2/7 + 5x = 1
    x = 1/7

    and then that same logic for the second die

    3n + 5n = 1
    n = 1/8

    so the probability is

    2/7*3/8 + 5*1/7*1/8
    = 11/56
     
    Last edited: Oct 27, 2014
  2. jcsd
  3. Oct 27, 2014 #2

    PeroK

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member

    It is all correct. Except, sadly, 2*3 = 6 (not 5)!
     
  4. Oct 27, 2014 #3
    I am so sorry, that was a big fail. Haha mixed up the + and *.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Probability with dice
  1. Dice Probability (Replies: 11)

  2. Dice Probability (Replies: 13)

  3. Dice and probability (Replies: 6)

Loading...