A pair of dice is loaded. The probability of 4 appearing on the first die is 2/7.
and the probability of a 3 appearing on the second die is thrice as much as the other numbers
on the die. If the rest of the numbers are equally likely events in both dice, what is the
probability of 7 appearing as the sum of the numbers when the two dice are rolled.
The Attempt at a Solution
So I was wondering if the answer I got is correct by chance. I took all the cases.
Got the probabilities and added them up. But I am not sure I got it right because it says the rest of the numbers are equally likely to appear, does that mean the probability of the rest in both dice is exactly the same. This is because if the probability of rolling a 4 on the first die is 2/7 then the rest are
2/7 + 5x = 1
x = 1/7
and then that same logic for the second die
3n + 5n = 1
n = 1/8
so the probability is
2/7*3/8 + 5*1/7*1/8