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Probably simple?

  1. Jan 14, 2014 #1
    1. So I have 2 equations:
    (1) A*cos(30)-1375*cos(x)=0
    (2) 1375*sin(x)+A*sin(30)-1500=0


    I redid equation (1) into A=1588*cos(x)
    And substituted it into equation (2).

    The result:

    1375*sin(x) + 794*cos(x) = 1500

    Can someone please tell me how to solve for x please?
     
  2. jcsd
  3. Jan 14, 2014 #2

    tiny-tim

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    Hi Xenix! Welcome to PF! :smile:

    (1375*cos(x))2 + (1375*sin(x))2 = … ? :wink:
     
  4. Jan 14, 2014 #3
    Hi!

    Thanks!

    (1375*cos(x))2 + (1375*sin(x))2 = 1

    But how does it help me?
     
  5. Jan 14, 2014 #4

    SteamKing

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    You can:
    1. Assume a solution and see if it satisfies the equation.
    2. Play around with trig identities to get all cosines or all sines in the equation.
    3. Plot the equation.
     
  6. Jan 14, 2014 #5

    tiny-tim

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    (13752, actually! :rolleyes:)

    come on … think! :smile:
     
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