Hi everyone,(adsbygoogle = window.adsbygoogle || []).push({});

I just would like to be reassured about simple probability question:

1. The problem statement, all variables and given/known data

A device is composed by two fragile pieces

during the warranty period the probability that:

-none is broken is 0,25

-both are broken is 0,25

-only one is broken is 0,25

If one piece is broken then the probability that it costs

-100$ is 1/2

-300$ is 1/3

-600$ is 1/6

What is the probability that the reparation costs 900$ ?

3. The attempt of a solution

- P = ( probability that both pieces are broken that the first costs 600$, the second 300$ and the first costs 300$ and the second 600$ )

= ( 0,25 * 1/3 * 1/6 ) * 2

Do you agree with me ?

Thanks!

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Probality easy question

Can you offer guidance or do you also need help?

Draft saved
Draft deleted

**Physics Forums | Science Articles, Homework Help, Discussion**