# Probality easy question

1. Dec 28, 2009

### penguin007

Hi everyone,
I just would like to be reassured about simple probability question:

1. The problem statement, all variables and given/known data

A device is composed by two fragile pieces
during the warranty period the probability that:
-none is broken is 0,25
-both are broken is 0,25
-only one is broken is 0,25
If one piece is broken then the probability that it costs
-100$is 1/2 -300$ is 1/3
-600$is 1/6 What is the probability that the reparation costs 900$ ?

3. The attempt of a solution

- P = ( probability that both pieces are broken that the first costs 600$, the second 300$ and the first costs 300$and the second 600$ )
= ( 0,25 * 1/3 * 1/6 ) * 2

Do you agree with me ?

Thanks!