Hi everyone, I just would like to be reassured about simple probability question: 1. The problem statement, all variables and given/known data A device is composed by two fragile pieces during the warranty period the probability that: -none is broken is 0,25 -both are broken is 0,25 -only one is broken is 0,25 If one piece is broken then the probability that it costs -100$ is 1/2 -300$ is 1/3 -600$ is 1/6 What is the probability that the reparation costs 900$ ? 3. The attempt of a solution - P = ( probability that both pieces are broken that the first costs 600$, the second 300$ and the first costs 300$ and the second 600$ ) = ( 0,25 * 1/3 * 1/6 ) * 2 Do you agree with me ? Thanks!