Probality easy question

  • Thread starter penguin007
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Hi everyone,
I just would like to be reassured about simple probability question:


Homework Statement




A device is composed by two fragile pieces
during the warranty period the probability that:
-none is broken is 0,25
-both are broken is 0,25
-only one is broken is 0,25
If one piece is broken then the probability that it costs
-100$ is 1/2
-300$ is 1/3
-600$ is 1/6
What is the probability that the reparation costs 900$ ?



3. The attempt of a solution


- P = ( probability that both pieces are broken that the first costs 600$, the second 300$ and the first costs 300$ and the second 600$ )
= ( 0,25 * 1/3 * 1/6 ) * 2

Do you agree with me ?


Thanks!
 

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