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I just would like to be reassured about simple probability question:

## Homework Statement

A device is composed by two fragile pieces

during the warranty period the probability that:

-none is broken is 0,25

-both are broken is 0,25

-only one is broken is 0,25

If one piece is broken then the probability that it costs

-100$ is 1/2

-300$ is 1/3

-600$ is 1/6

What is the probability that the reparation costs 900$ ?

**3. The attempt of a solution**

- P = ( probability that both pieces are broken that the first costs 600$, the second 300$ and the first costs 300$ and the second 600$ )

= ( 0,25 * 1/3 * 1/6 ) * 2

Do you agree with me ?

Thanks!