Originally posted in a technical math section
It is a problem found on IB math SL book:

The two perpendicular sides of a right-angled triangle have lengths x+2 and 5x-3, the hypotenuse has length 4x+1, Find X.

In the answer section, it says X is either 2/5 or 3.

I tried a lot, -> i arrived to 10x^2 - 18x -12= 0
Later i used quadractic formula and imy result is totally different to the answers given by the book,. My process should be wrong. I would like to see someone do the complete process so i can notice my error. Please!! Currently studying for IB exam

Last edited:

Mark44
Mentor
It is a problem found on IB math SL book:

The two perpendicular sides of a right-angled triangle have lengths x+2 and 5x-3, the hypotenuse has length 4x+1, Find X.

In the answer section, it says X is either 2/5 or 3.
richardz03 said:
I tried a lot, -> i arrived to 10x^2 - 18x -12= 0
richardz03 said:
Later i used quadractic formula and imy result is totally different to the answers given by the book,. My process should be wrong. I would like to see someone do the complete process so i can notice my error. Please!! Currently studying for IB exam
No, we aren't going to work the problem for you -- that is against forum rules. Show the work you did to get your equation, and we'll point out where you went wrong, and steer you in the right direction.

richardz03
SammyS
Staff Emeritus
Homework Helper
Gold Member
It is a problem found on IB math SL book:

The two perpendicular sides of a right-angled triangle have lengths x+2 and 5x-3, the hypotenuse has length 4x+1, Find X.

In the answer section, it says X is either 2/5 or 3.

I tried a lot, -> i arrived to 10x^2 - 18x -12= 0
Later i used quadratic formula and my result is totally different to the answers given by the book,. My process should be wrong. I would like to see someone do the complete process so i can notice my error. Please!! Currently studying for IB exam
It looks like you made a mistake in getting that quadratic equation.

richardz03