Originally posted in a technical math section
It is a problem found on IB math SL book:

The two perpendicular sides of a right-angled triangle have lengths x+2 and 5x-3, the hypotenuse has length 4x+1, Find X.

In the answer section, it says X is either 2/5 or 3.

I tried a lot, -> i arrived to 10x^2 - 18x -12= 0
Later i used quadractic formula and imy result is totally different to the answers given by the book,. My process should be wrong. I would like to see someone do the complete process so i can notice my error. Please!! Currently studying for IB exam

Last edited:

Mark44
Mentor
It is a problem found on IB math SL book:

The two perpendicular sides of a right-angled triangle have lengths x+2 and 5x-3, the hypotenuse has length 4x+1, Find X.

In the answer section, it says X is either 2/5 or 3.
richardz03 said:
I tried a lot, -> i arrived to 10x^2 - 18x -12= 0
richardz03 said:
Later i used quadractic formula and imy result is totally different to the answers given by the book,. My process should be wrong. I would like to see someone do the complete process so i can notice my error. Please!! Currently studying for IB exam
No, we aren't going to work the problem for you -- that is against forum rules. Show the work you did to get your equation, and we'll point out where you went wrong, and steer you in the right direction.

• richardz03
SammyS
Staff Emeritus
Homework Helper
Gold Member
It is a problem found on IB math SL book:

The two perpendicular sides of a right-angled triangle have lengths x+2 and 5x-3, the hypotenuse has length 4x+1, Find X.

In the answer section, it says X is either 2/5 or 3.

I tried a lot, -> i arrived to 10x^2 - 18x -12= 0
Later i used quadratic formula and my result is totally different to the answers given by the book,. My process should be wrong. I would like to see someone do the complete process so i can notice my error. Please!! Currently studying for IB exam
It looks like you made a mistake in getting that quadratic equation.

• richardz03