- #1

confused

I just wanted to check up on a problem I just did.

The problem is:

**A vall is thrown by a baseball player. The ball is released from the player's hand at an angle of 35 degrees above the horizontal direction at a height of 2.0 meters above the playing field. The ball lands on the field 3 seconds later after it leaves the players hand. What is the inital speed of the ball as it leaves the players hand**

This is how I attempted to solve the problem, but not sure if it is correct or not.

**known variables**

y=2.0m

t=3.00s

a=-9.8m/s^2

angle = 35 degrees

first, find the inital speed in the y direction:

y=vo(t)+.5(g)(t)^2

2.0m=vo(3.00s)+.5(-9.8)(3.00s)^2

v=15.37 m/s

now make this a y-component vector and find the x component of this vector by taking the Vi of y and dividing it by (tan 35). I get 20.39 m/s. Now since the speed is the magnitude of the velocity, take the magnitude of both the x and y components of the Vi vector and I get:

**25.35**m/s.

Any help would be greatly appreciated.