Hi all, I just wanted to check up on a problem I just did. The problem is: A vall is thrown by a baseball player. The ball is released from the player's hand at an angle of 35 degrees above the horizontal direction at a height of 2.0 meters above the playing field. The ball lands on the field 3 seconds later after it leaves the players hand. What is the inital speed of the ball as it leaves the players hand This is how I attempted to solve the problem, but not sure if it is correct or not. known variables y=2.0m t=3.00s a=-9.8m/s^2 angle = 35 degrees first, find the inital speed in the y direction: y=vo(t)+.5(g)(t)^2 2.0m=vo(3.00s)+.5(-9.8)(3.00s)^2 v=15.37 m/s now make this a y-component vector and find the x component of this vector by taking the Vi of y and dividing it by (tan 35). I get 20.39 m/s. Now since the speed is the magnitude of the velocity, take the magnitude of both the x and y components of the Vi vector and I get: 25.35m/s. Any help would be greatly appreciated.