- #1
mobilesystem
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Hello to all ,
I need your help again , if you can .
My question is about a problem / exercise book solved Aircraft Structures for Engineering Students - 5ed , example 20.4 .
So the problem this section supports a vertical load of 10kN and the objective is to calculate the flow section in FIG .
The areas of booms are: B1 = B8 = 200mm ^ 2 B2 = B7 = 250mm ^ 2 B3 = B6 = 400mm ^ 2 B4 = B5 = 100mm ^ 2
http://imageshack.us/photo/my-images/811/0u2h.jpg/
Solving we have:
The shear flow is given by :
http://imageshack.us/photo/my-images/35/f5m4.jpg/
But given that the section is symmetrical , the value of Ixy = 0 and as we have no strength x then Sx = 0, so the expression is :
http://imageshack.us/photo/my-images/853/a1fe.png/
And Ixx = 13.86 * 10 ^ 4 ^ 6 mm
The above equation becomes:
http://imageshack.us/photo/my-images/577/v8dd.png/
Cutting the bar in section 23 , we can calculate the shear flow in the sections :
http://imageshack.us/photo/my-images/690/vrtl.png/
And now we have a serious problem :
I do not know how to calculate the moments that appear in the image below :
http://imageshack.us/photo/my-images/841/24i6.png/
The expected value of qs , 0 result is : qs , 0 = -5.4N/mm in the counterclockwise direction , as can be seen in the image below .
http://imageshack.us/photo/my-images/20/dzgi.png/
Things to know :
The value of 97200 refers to the internal area of the figure :
The 2 refers to the symmetry of the bars and the rest do not know .
All help is welcome.
Hug and Thanks
I need your help again , if you can .
My question is about a problem / exercise book solved Aircraft Structures for Engineering Students - 5ed , example 20.4 .
So the problem this section supports a vertical load of 10kN and the objective is to calculate the flow section in FIG .
The areas of booms are: B1 = B8 = 200mm ^ 2 B2 = B7 = 250mm ^ 2 B3 = B6 = 400mm ^ 2 B4 = B5 = 100mm ^ 2
http://imageshack.us/photo/my-images/811/0u2h.jpg/
Solving we have:
The shear flow is given by :
http://imageshack.us/photo/my-images/35/f5m4.jpg/
But given that the section is symmetrical , the value of Ixy = 0 and as we have no strength x then Sx = 0, so the expression is :
http://imageshack.us/photo/my-images/853/a1fe.png/
And Ixx = 13.86 * 10 ^ 4 ^ 6 mm
The above equation becomes:
http://imageshack.us/photo/my-images/577/v8dd.png/
Cutting the bar in section 23 , we can calculate the shear flow in the sections :
http://imageshack.us/photo/my-images/690/vrtl.png/
And now we have a serious problem :
I do not know how to calculate the moments that appear in the image below :
http://imageshack.us/photo/my-images/841/24i6.png/
The expected value of qs , 0 result is : qs , 0 = -5.4N/mm in the counterclockwise direction , as can be seen in the image below .
http://imageshack.us/photo/my-images/20/dzgi.png/
Things to know :
The value of 97200 refers to the internal area of the figure :
The 2 refers to the symmetry of the bars and the rest do not know .
All help is welcome.
Hug and Thanks