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Problem from Amc involving logs

  1. Sep 1, 2012 #1
    The Following is defined,


    where x > c, what is c?

    Answer is 2001^2002, but how to obtain it?

    I do not know much about logs as I am only in precalculus.
  2. jcsd
  3. Sep 1, 2012 #2

    Remember that (the real) logarithm function at any base is defined only on the real positive numbers, thus it must be
    (I'm assuming that those numbers you wrote in such an unclear way are the logarithms' bases), and from here
    $$\log_{2002}(\log_{2001}(x))>1\Longrightarrow \log_{2001}(x)>2002\Longrightarrow...etc $$

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