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Problem involing an arrow

  1. Dec 13, 2007 #1
    Robin Hood is walking through Sherwood Forest when he comes upon the Sheriff of Nottingham. The Sheriff tells Robin Hood he is going to arrest him for numerous misdeeds. Robin pulls out his bow, loads an arrow, pulls the bow back 0.70 m, and shoots an arrow into the Sheriff's hat, knocking the hat with the arrow lodged in it off his head. The hat's mass is 0.5 kg. It takes 4N to pull Robin's bow back 0.10 m, and the arrow has a mass of 0.20 kg.
    a) What is the speed of the hat with the arrow in it just after it is struck? Assume the arrow travels horizontally between Robin and the Sheriff and neglect air resistance.
    b) If the Sheriff is 2.0 m high, how far behind him will his hat with the arrwo in it hit the ground?

    For (a) I used F=kx and found it to be 40 N/m
     
  2. jcsd
  3. Dec 13, 2007 #2

    Doc Al

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    OK, you found the value of k, the spring constant of the bow. Keep going. How much energy does the arrow have after it leaves the bow?
     
  4. Dec 13, 2007 #3
    I found the energy to be:

    W = 1/2(k)(x)^2
     
  5. Dec 13, 2007 #4

    Doc Al

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    Good. Keep going. What's the arrow's speed just before it hits the hat? Then figure out the speed of "hat + arrow" after the the arrow hits the hat.

    Hint: Treat the arrow sticking into the hat as an inelastic collision. What's conserved?
     
  6. Dec 13, 2007 #5
    I found that the speed of the arrow before the collision was:
    KE = 1/2mv^2
    9.8 J = 1/2(0.2 kg)(v)^2
    v = 98 m/s

    And used the equation:
    m1v1i + m2v2i = (m1 + m2)vf
    And found that the final velocity was 2.8 m/s

    How do you start part (B)
     
  7. Dec 13, 2007 #6

    Doc Al

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    Part (B) is a projectile motion problem. You just found the initial velocity, which is horizontal. How long does it take before it hits the ground?
     
  8. Dec 13, 2007 #7
    Would I use F=ma to find the acceleration and then plug that into v=v0 + at to find the time?
     
  9. Dec 13, 2007 #8

    Doc Al

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    You'd be better off using a different formula, since you don't have the final velocity in the vertical direction. You have the distance, so find a kinematic formula with distance and time.

    You shouldn't have to use F=ma to find the acceleration (though you could, of course). Since this is just a projectile, you should know the acceleration.
     
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