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Problem on an inclined plane

  1. Feb 16, 2010 #1
    1. The problem statement, all variables and given/known data

    A 3kg load on an inclined plane of angel 30 degrees is connected by a cord over a frictionless pulley to a second load which has a mass of 2 kg. Find the:

    a) Acceleration of each load
    b) tension of each chord


    2. Relevant equations

    none?


    3. The attempt at a solution

    block A / box on inclined plane

    [tex]\sum[/tex]Fy= 0
    -Wycos30[tex]\circ[/tex] + NF= 0
    -30cos30 + NF = 0
    -25.98 + NF = 0
    -25.98 = NF
    NF = 25.98

    f=[tex]\mu[/tex] NF
    f= 0.3 (25.98)
    f= 7.794

    [tex]\sum[/tex]Fx= ma
    Wxsin30[tex]\circ[/tex] - T - f = ma
    15 - T - 7.794 = ma
    15 - 7.794 - T = (3)(a)
    -T = 3a - 7.206
    T = 7.206 - 3a

    block b

    [tex]\sum[/tex]Fx= ma
    T-W = ma
    T - (2)(10) = (2)a
    T - 20 = 2a
    T= 2a+20

    T=T
    2a+20 = 7.206 - 3a
    2a+3a = 7.206 - 20
    5a = -12.794
    a = - 2.56 m/s2

    T1=7.206 - 3a
    T= 7.206- 3(-2.56)
    T= 14.886 N

    T2= 2a+20
    T= 2(-2.56) + 20
    T= -3.1176 N

    T2+T1 = TotalT
    14.886 + (-3.1176) = TotalT
    TotalT= 11.7684 N

    I'm not sure if I got the right answer :( someone help?
     
  2. jcsd
  3. Feb 16, 2010 #2

    rl.bhat

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    Homework Helper

    Loads are connected by a single cord. So T1 = T2 = T.
     
  4. Feb 16, 2010 #3
    so the tensions I got are incorrect then? :frown:
    may I ask if the acceleration is correct?
     
  5. Feb 16, 2010 #4

    rl.bhat

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    Homework Helper

    Your acceleration is correct.
     
  6. Feb 16, 2010 #5
    thank you ! :) so I only need to use one equation for my tension, and that's the answer? thank you very much again :) I really appreciate it ^^
     
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