- #1

- 18

- 0

Can anyone help me with this problem? I'm just not understanding it...any help would be appreciated.

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter echau
- Start date

- #1

- 18

- 0

Can anyone help me with this problem? I'm just not understanding it...any help would be appreciated.

- #2

Doc Al

Mentor

- 45,078

- 1,382

- #3

Astronuc

Staff Emeritus

Science Advisor

- 19,222

- 2,686

So this becomes an electrostatic force problem - the alpha stops.

Remember coulombs law and coulomb force.

What is the electric field cause due to 79q, where q is the magnitude of charge on a proton?

acceleration, a = F/m.

- #4

- 18

- 0

Should I use F=kq1q2/r^2? then plug it into F=ma?

or should I find E=kq/r^2 and plug it into F=qE?

Sorry if these are very simplistic questions...Physics is hard for me =/

- #5

Doc Al

Mentor

- 45,078

- 1,382

The two approaches are identical. Take your pick.echau said:Should I use F=kq1q2/r^2? then plug it into F=ma?

or should I find E=kq/r^2 and plug it into F=qE?

- #6

- 18

- 0

thank you :) i really appreciate the help!

- #7

lightgrav

Homework Helper

- 1,248

- 30

the first approach ignores the E-field, which WAS the Question.

- #8

Doc Al

Mentor

- 45,078

- 1,382

As far as figuring out the acceleration, the two methods for finding the force are identical. But since you have to find the electric field anyway, obviously you would use that result to finish the problem.

Share: