A cage holds a 150g mass, which is attached to one end of a spring the other end of the spring is attached to the opposite end of th ecage. The spring is streched 4.0 cm as the mass is whirled at 25.0 rev/s in a circle of radius 6.0 cm about the center of the cage on a horizontal frictionless surface as indicated in Figure P.6 (Hopefully you can understand it without the image ;\). What is the spring constant?(adsbygoogle = window.adsbygoogle || []).push({});

anyway, I'm trying to use the formula

Fspring = -Kx k is the constant.

I think xf - xi = .04m - 0m = .04 = x

I don't know how to get the force though... I split it as F=ma

then I know the mass.. .150kg, but I don't know how I can get the acceleration from the 25.0 rev/s

I'm confused [b(] Can someone help me!!!!?? =)

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# Homework Help: Problem on Hooke's force law

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