# Problem on Ohm's Law

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1. May 27, 2015

### 22990atinesh

1. The problem statement, all variables and given/known data
In the circuit shown the value of I in ampere is

2. Relevant equations
$V = I R$

3. The attempt at a solution
Leaving 4 ohm above resistor Equivalent R will be
$R_{eq} = \frac{4*4}{4+4} + 4 + 1.6 = 7.6$
$I = \frac{V}{R}$
$I = \frac{4}{7.6} = 0.526$
Ans is not given in the option please tell what I'm doing wrong

2. May 27, 2015

### Orodruin

Staff Emeritus
Why do you think you can ignore the top resistor?

Also, note that the middle contraption is two 4 ohm resistors in parallel with a wire of resistance zero ...