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Problem on Ohm's Law

  1. May 27, 2015 #1
    1. The problem statement, all variables and given/known data
    In the circuit shown the value of I in ampere is
    [img=http://s28.postimg.org/5adobnb95/Capture.jpg]

    2. Relevant equations
    ## V = I R ##

    3. The attempt at a solution
    Leaving 4 ohm above resistor Equivalent R will be
    ##R_{eq} = \frac{4*4}{4+4} + 4 + 1.6 = 7.6##
    ##I = \frac{V}{R}##
    ## I = \frac{4}{7.6} = 0.526 ##
    Ans is not given in the option please tell what I'm doing wrong
     
  2. jcsd
  3. May 27, 2015 #2

    Orodruin

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    Why do you think you can ignore the top resistor?

    Also, note that the middle contraption is two 4 ohm resistors in parallel with a wire of resistance zero ...
     
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