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Problem solving for x

  1. Oct 25, 2004 #1
    I am having trouble solving for the two values
    of (x) that are closest to zero.

    -30 sin 3x = 1/10 cos 3x

    Is there a formula I could use to make this easy?
  2. jcsd
  3. Oct 25, 2004 #2


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    Dearly Missed

    Write this as an equation in tan(3x)..
  4. Oct 25, 2004 #3
    sin(x)/cos(x) = tan(x)

    to see why this is true Draw a right triangle with hypotenuse 1 and an acute angle x, you can work the sides of the right triangle have lengths sin(x) and cos(x).
  5. Oct 25, 2004 #4
    Oh yea! I just forgot!

    Thank you!
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