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There is a question in Calculus By James Stewart (5e) that says:

Find the horizontal and vertical asympotes of

[tex]y = \frac{x^2 + 4}{x^2 - 1}}[/tex]

I put it in limit as

[tex]\lim_{\substack{x\rightarrow \infty}} \frac{x^2 + 4}{x^2 - 1}}[/tex]

and divided the numeratir abd denominator by[tex]x^2[/tex]

and I got [tex]\frac{1}{1}} = 1[/tex] which would be the horizontal asympotes.

And then I stopped here I don't know how to find the vertical asympote and i'm not sure about the horizontal asympote.

The examples in the book doesn't look the same. Each time they use different method to solve them. And now I'm getting confused.

Can someone help ?

Thanks

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# Problem with a limit as infinity

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