Find n so that:
1/(1+√3) + 1/(√3+√5) + 1/(√5+√7) + .... + 1/(√2n-1 + √2n+1) = 100
Find n so that the same sum equals any number x (instead of 100)
sum (1/(√2n-1 + √2n+1) = 100
The Attempt at a Solution
i have proven using the first 3 given terms that this series cannot be geometric or arithmatic. But if its neither how does my teacher expect me to find when the series equals 100?
what do i do? where do i go from here?