- #1

- 1,629

- 1

## Main Question or Discussion Point

Hello everyone i'm having problems proving this:

note: A' will stand for complemented;

AB + BC'D' + A'BC + C'D = B + C'D

B(A+C'D')

B(A+C'+D')

BA + BC' + BD' + A'BC + C'D

BA + BD' + A'BC + C'(B+D)

B(A + D' + A'C) + C'(B+D)

now i'm stuck, i don't see how that is going to work out. Any help would be great.

note: A' will stand for complemented;

AB + BC'D' + A'BC + C'D = B + C'D

B(A+C'D')

B(A+C'+D')

BA + BC' + BD' + A'BC + C'D

BA + BD' + A'BC + C'(B+D)

B(A + D' + A'C) + C'(B+D)

now i'm stuck, i don't see how that is going to work out. Any help would be great.