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Problem with density

  1. Sep 11, 2004 #1
    does anyone know how to solve this problem? ive been trying to figure it out for so long but obviously i cant. heres the problem:

    Density of seawater is 1.1g/cm cubed. Determine the mass of 10mile cubed of seawater.

    thanks :smile:
  2. jcsd
  3. Sep 11, 2004 #2
    i can show you the units but you will have to look up the conversion factors.

    1.1 g seawater/cm^3 x 100^3 cm^3/1m^3 x (how ever many meters in 1 mile)^3 m^3/mi^3 x 10 mi^3= x g of seawater.
  4. Sep 11, 2004 #3
    Well, density is Mass divided by Volume

    d = m/v

    d(v) = m

    So, you only need to convert 10 miles cubed into centimeters cubed.

    Just look up on a simple conversion table.

    Mile to Cm conversion.. hmm.. *pulls out chemistry text book*
    Well, I've only got miles to km here, which is 1 mi = 1.609 km.
    Soo... that means 10(1.609x10^5) will give you your volume.

    10^5 because kilo--> centi has a five place difference.
    Kilo is 1000 and centi is .01
    So that means there is 10^5 centimeters in one kilometer.

    Then just divide.

    I think that's correct.
    We're doing this same thing in my General Chemistry I course.
  5. Sep 11, 2004 #4


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    density should be in g/cm^3, the latter corresponds to mass/volume. You need to convert a cube having a volume of 10 x 10 x 10 miles, to cm^3...its standard factor label calculations.
  6. Sep 12, 2004 #5


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    I'm sure Azrioch meant to write 10(1.609x10^5)^3, which would be the correct conversion of 10 cubic miles into cubic centimeters.

    Just to make sure there's no misunderstanding arising out of convention, this is
    [tex] 10 * (1.609*{10}^5)^3 [/tex]
    Last edited: Sep 12, 2004
  7. Sep 12, 2004 #6
    Ah, yes, whoops...

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