1. The problem statement, all variables and given/known data Let a,b,c be positive real numbers. Prove that: a3+b3+c3≥a2b+b2c+c2a 2. Relevant equations 3. The attempt at a solution I assumed that a≥b≥c>0 following which I shifted the left side of this inequality to the right side giving a3+b3+c3-(a2b+b2c+c2a)≥0 How do I do the required factorisation ... ???