- #1
Sam Morse
- 15
- 0
Homework Statement
Let a,b,c be positive real numbers. Prove that:
a3+b3+c3≥a2b+b2c+c2a
Homework Equations
The Attempt at a Solution
I assumed that a≥b≥c>0 following which I shifted the left side of this inequality to the right side giving
a3+b3+c3-(a2b+b2c+c2a)≥0
How do I do the required factorisation ... ?