(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A patient's leg is held in position by 2 weights tht are connected through cables. The weight of the leg is W = 300N. L is the horizontal distance between the points where the cables connect with the leg (points A and B) and C is the center of gravity for the leg, located 2/3 L away from A. The angles from cable 2 is Beta=45 degrees.

Find T1, T2, W1, W2, and the angle Alpha for the leg to stay in equilibrium.

[PLAIN]http://img820.imageshack.us/img820/2055/drawing5.jpg [Broken]

2. Relevant equations

Sum of Fy=0

Sum of Fx=0

Sum of Moments = 0

3. The attempt at a solution

So I separated the pulleys, so have for the weight and pulleys on left:

Sum of Fy= T1-W1=0

For the weight and pulleys on right:

Sum of Fy=T2-W2=0 (is this correct? What is the effect of the second pulley on the tension?)

Sum of Fy= T1sin(Alpha) - W +T2sin(45)

(Should these be T1sin and T2 sin or just T1 and T 2?)

Then I did sum of moments:

Sum of moments around point A = -W*2L/3 + T2sin(45)*L=0

Sum of moments around C = -T1sin(Alpha)*2L/3 + T2sin(45)*L/3

Sum of moments around B = W*L/3 + T1sin(Alpha)*L

So basically I'm stuck. Not sure if so far it's correct of how to proceed.

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# Problem with pulleys

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